4v^2+15v+11=0

Solution for 4v^2+15v+11=0 equation:

4v^2+15v+11=0

a = 4; b = 15; c = +11;
Δ = b2-4ac
Δ = 152-4·4·11
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-7}{2*4}=\frac{-22}{8}
=-2+3/4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+7}{2*4}=\frac{-8}{8}
=-1
$